Y=2.304-5x^2+3

Solution for Y=2.304-5x^2+3 equation:

=2.304-5Y^2+3

We move all terms to the left:

-(2.304-5Y^2+3)=0

We get rid of parentheses

5Y^2-2.304-3=0

We add all the numbers together, and all the variables

5Y^2-5.304=0

a = 5; b = 0; c = -5.304;
Δ = b2-4ac
Δ = 02-4·5·(-5.304)
Δ = 106.08
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{106.08}}{2*5}=\frac{0-\sqrt{106.08}}{10}
=-\frac{\sqrt{}}{10}
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{106.08}}{2*5}=\frac{0+\sqrt{106.08}}{10}
=\frac{\sqrt{}}{10}
$